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Mathematics 18 Online
OpenStudy (anonymous):

Differentiate; x^2/(1+x)^2

OpenStudy (ajprincess):

This is of the form u/v. (u/v)'=(u'v-v'u)/v^2 Here u=x^2 and v=(1+x)^2. (x^n)'=nx^(n-1) Can u do it @emcrazy14?

OpenStudy (anonymous):

I got the answer -2x/(1+x)^3. Is it correct?

OpenStudy (experimentx):

differentiate: 1/(1/x + 1)^2

OpenStudy (ajprincess):

check the sign @emcrazy14. It shud be 2x/(1+x)^3

OpenStudy (anonymous):

Ok, thanks. Do I multiply (x+1) with a negative sign to change it into (1+x) so that it cancels with the the denominator (1+x)^4?

OpenStudy (experimentx):

just ask the wolf for differentiation Question.

OpenStudy (ajprincess):

nope. (x+1)=(1+x)

OpenStudy (anonymous):

Then how oes it become +2x? :O

OpenStudy (anonymous):

@experimentX : wolf? :O *does

OpenStudy (ajprincess):

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