Question

Find the constant k so that the quadratic equation 2x^2 + 5x - k = 0 has two real solutions?

Answer 1

Quadratic Formula!!! :D

Answer 2

First you find the delta:

b^2-4ac
5^2-4(2)(-k)
25+8k

because it has two real solutions..so,

25+8k>0
8k>-25
k>-25/8

Answer 3

Good Job u got it 1st!!!!!

Answer 4

\[\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}\]
Yeah, as per @aroub
delta (I thought it was discriminant)
determines the number of roots you have, as well as their nature...
Delta is that expression in the radical in the quadratic formula :D

Answer 5

It is discriminant but i didn't need a quadratic formula.

Answer 6

When you want to find K, no need!

Answer 7

i know!!! Thanks

Answer 8

No problem!!