Find the constant k so that the quadratic equation 2x^2 + 5x - k = 0 has two real solutions?

Question

terenzreignz · Answer

Quadratic Formula!!! :D

aroub · Answer

First you find the delta: 

b^2-4ac
5^2-4(2)(-k)
25+8k 

because it has two real solutions..so, 

25+8k>0 
8k>-25
k>-25/8

highlyeducated87 · Answer

Good Job u got it 1st!!!!!

terenzreignz · Answer

$$\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$$
Yeah, as per @aroub 
delta (I thought it was discriminant)
determines the number of roots you have, as well as their nature...
Delta is that expression in the radical in the quadratic formula :D

highlyeducated87 · Answer

It is discriminant but i didn't need a quadratic formula.

aroub · Answer

When you want to find K, no need!

highlyeducated87 · Answer

i know!!! Thanks

aroub · Answer

No problem!!