Question

8 < x(7 – x)

Answer 1

start with
\[8<7x-x^2\] then
\[x^2-7x+8<0\]

Answer 2

you are going to have so finish by solving
\[x^2-7x+8=0\] using the quadratic formula
once you know the zeros, since this is a parabola that opens up, it will be negative between the zeros, which is what you are looking for

Answer 3

HELP

Answer 4

i think its 0

Answer 5

x=(-b+-sqrt(b^2-4ac))/2a
x=(-(-7)+-sqrt((-7)^2-4*1*8))/2*1
x=(7+-sqrt(49-32))/2
x=(7+-sqrt(17))/2
x1=(7+sqrt(17))/2
x2=(7-sqrt(17))/2
now, plug these points to line number