It is possible to apply ratio test two times in an exercise ?

Question

nubeer · Answer

hmm no.. i think its just applied once.. as far as i remember when i use to do it 2 times the answer was never right for me.

anonymous · Answer

ok then the limit after i applied it once is lim((n+1)^2/2^(2n+1)) and i don't know if it's infinite or not

nubeer · Answer

in ratio test the limit always approaches to infinity.. infact in every test limit approaches infinity.

anonymous · Answer

yes but in this case i have to know if it's <1 or >1....

nubeer · Answer

yes thats what we find through ratio test... u can tell me at what part you are stuck

anonymous · Answer

after i applied ratio test i have the limit i wrote and i don't know what is  the value of it

anonymous · Answer

$$\sum_{n=1}^{\infty}(n!)^2/2^n$$

anonymous · Answer

but n on the denominator is at the power 2(i don't know how to write it)

anonymous · Answer

2^n^2 the denominator

nubeer · Answer

ok seems like you have done mistakes while solving..
|dw:1352539457202:dw| this is your inital question right?