Question

Factor: \[1-\frac{ \sin^2x }{ 1+ cosx }\]

Answer 1

write sin^2 x as 1-cos^2 x

Answer 2

then use \(
a^2-b^2=(a+b)(a-b)\)

Answer 3

which gives you \(\huge \sin^2x=(1-\cos x)(1+\cos x)\)

Answer 4

did u get that ?

Answer 5

@johnnyalln
a response is expected.....

Answer 6

Got ya! Yes i was trying to write it all out as you explained

Answer 7

ok...good, so what u gor finally ?

Answer 8

*got

Answer 9

still working it :) one sec

Answer 10

I just get cos x...

Answer 11

1-(1-cos x) = 1-1+cos x
=cos x
you are correct :)

Answer 12

awesome! thank you so much!

Answer 13

welcome :)