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Mathematics 11 Online
OpenStudy (anonymous):

Probability: Please answer the question attached. Shouldn't this be (1/12)*(1/11)*(1/10)*(1/9)*(1/8) since these are independent events?

OpenStudy (anonymous):

OpenStudy (anonymous):

Yes. However, there isn't an answer.

OpenStudy (anonymous):

Thx for confirming that!

OpenStudy (anonymous):

lol You're welcome :)

OpenStudy (anonymous):

its D. the possible combinations is 12!/7!5! and that is 792. The possible ways to win is one so 1/792 and thats .0012626262626262626262.... rounding off we get .0013.

OpenStudy (anonymous):

Aren't these 12 distinct numbers, in which there act like alphabets?

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