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Algebra
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Suppose a parabola has a vertex (-8,-7) and also passes through the point (-7,-4). write the equation of the parabola in vertex form.
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\(y+7=3(x+8)^2\)
The answer is y=3(x+8) -7 .. I just dont know how to get it
Vertex form is: \[a(x-h)^{2}+k\]
\[(h,k) \] is your vertex
I know that but when I plug the problem into it I don't get the correct answer. What am I doing wrong. Can you please explain how to do it to me
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So -8 and -7 are vertex
-8 = h -7= k
a ( -7+8) Squared + 7 is that right
Subtract -7 from both sides of my equation.
No.
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