Mathematics
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OpenStudy (pottersheep):
I really need help with this Trig identity please!(Grade 12!)
How do I prove that sinx-siny = 2cos([x+y]/2)sin([x+y]/2)
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OpenStudy (pottersheep):
I've been at it for so long! I cant get it :(
OpenStudy (anonymous):
I can help.
OpenStudy (pottersheep):
Thank you so much
OpenStudy (pottersheep):
We have only learnt compound angles, by the way
OpenStudy (anonymous):
So there is an identity that's called co function identies, do you know them?
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OpenStudy (pottersheep):
I think so
OpenStudy (anonymous):
Or sum to product identities. Do any of these sound familiar.
OpenStudy (pottersheep):
Is it the cos(90-x) kind of thing?
OpenStudy (anonymous):
um, not really. Here, let me post a link.
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OpenStudy (pottersheep):
Thanks Ill read it!
OpenStudy (pottersheep):
nope....never learnt those :s
OpenStudy (anonymous):
Okay.
OpenStudy (anonymous):
Give me like 5-10 minutes. This one is a little tricky. I'll try to keep you updated with the steps.
OpenStudy (pottersheep):
Alright I really appreciate it
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OpenStudy (pottersheep):
I found a note that our teacher wrote on the board! I dont get it though...
he wrote
OpenStudy (pottersheep):
sinx + siny = sin(a+b) = sinacosB + cosAsinB
sin(a-b) = sinAcosB - cosAsinB
sin(a+B) + sin (a - b) = 2sinAcosB
OpenStudy (pottersheep):
ignore the caps they are the same letter
OpenStudy (pottersheep):
Then he wrote : let : a+b = x
a - b = y
2a = x+y
x = (x+y)/2
OpenStudy (anonymous):
still working....
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OpenStudy (anonymous):
Okay, Do you know the double angle formula?
OpenStudy (pottersheep):
yep!
OpenStudy (anonymous):
good.
OpenStudy (anonymous):
okay, so cos([x+y]/2)sin([x+y]/2).
This equal sin(x+y)
OpenStudy (anonymous):
Are you following what i mean here?
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OpenStudy (pottersheep):
hmm
OpenStudy (anonymous):
how about this.
2cosAsinA=sin2a. A=(x+y)/2
OpenStudy (pottersheep):
alright
OpenStudy (anonymous):
cosine of x is sine of (90-x) right?
OpenStudy (pottersheep):
yep
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OpenStudy (anonymous):
okay. so
=sin(x+y)
=sinxcosy+sinycosx
=sinx sin(90-y)+siny sin(90-x)
OpenStudy (pottersheep):
yep
OpenStudy (anonymous):
I have a quick question, is it sin(x+y)/2 or sin(x-y)/2?
OpenStudy (pottersheep):
one sec for the original question?
OpenStudy (anonymous):
yes.
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OpenStudy (pottersheep):
oh no! you are right it sin(x-y)!!!!!!!
OpenStudy (pottersheep):
sorry ><
OpenStudy (anonymous):
Ok, that makes more sense now.
OpenStudy (anonymous):
Give me another minute to type this up.
OpenStudy (pottersheep):
Of course
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OpenStudy (anonymous):
ok, i've got it.
OpenStudy (pottersheep):
:D
OpenStudy (anonymous):
OpenStudy (anonymous):
ok let me know if you can see it.
OpenStudy (pottersheep):
I can see it! Im following through fine so far. Thank you so much
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OpenStudy (anonymous):
Yep.