Simplify completely
\[\frac{ x^2-4x+4 }{ x^2+10x+25 }\times \frac{ x+5 }{ x^2+3x-10}\]
Have you factored the quadratics on both sides?
i dont know how
(x-2)(x-2)(x+5) -------------------- (x+5)(x+5)(x+5)(x-2)
I factorized the top left numerator. (x-2)(x-2)
Now which "factors" cancel by division?
what do you mean?
When something appears both in the numerator (top) and in the denominator (bottom), they equal 1. We don't write the 1 when that happens.
the (x+5)?
Yes. One (x+5) disappears and one (x-2) disappears. They became 1s. When you multiply anything by 1, it is unchanged. This is why we don't write the 1 upon dividing.
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So you are left with (x-2) ---------- (x+5)(x+5) You can write the bottom as (x+5)^2 or x^2+10x+25
would the top be x-2 or (x-2)^2?
There is only one factor of (x-2) Leave it alone.
The (^2) means there are TWO terms multiplied together. For example: 2^2 = 2*2
Thanks!
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