the more complete answers are really helping with my understanding, x=t-1 and y=t^2-4t i know that x rearranged gives x+1=t but i got stuck with y so far i have y+4t =t^2 can anyone help me further (eliminate parameter t and describe object)

Question

anonymous · Answer

y+4t=t^2
solving this for t involves quadratics

anonymous · Answer

@rwinnie2 
you basically use the quadratic formula $$t=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }$$
but first u are going to get the equation in the form t^2 -4t =y
then u have:
a=1
b=-4
and
c=0
then plug the values and find the value of t
assume t is x

anonymous · Answer

wait sorry i might be wrong about all this but are u using this x+1=t to find for y+4t =t^2 ?

anonymous · Answer

if its that then u basically plug the x+1 for t in y+4t =t^2
so y+4(x+1)=(x+1)^2

anonymous · Answer

then that is y+4x+4 = (x+1)(x+1)

anonymous · Answer

(x+1)(x+1)
that is x^2 +2x +1
so 
y+4x+4 = x^2 +2x +1
y = x^2 + 2x +1- 4x - 4
which is
y=x^2 - 2x - 3

anonymous · Answer

is it making sense or am i right @rwinnie2

anonymous · Answer

ok that makes sense, but whether or not your right i have no clue, i was ill for the class and was set the classwork as homework with no additional help whatever, i did ask but he said he is busy and he will sort something out, but he wants it handed in for Thursday??????? but thank you so much i need all the help i can get