logbase8(x+6) + (x+3)=2

Please help me solve this... need the exact solution and decimal approximation

Question

logbase8(x+6) + (x+3)=2

Please help me solve this... need the exact solution and decimal approximation

tkhunny · Answer

Is it $$\log_{8}(x+6) + (x+3) = 2$$

anonymous · Answer

Yes! thank u sorry i didn't know how to type log base 8. how do you type it?

tkhunny · Answer

It helps to learn a little LaTeX.  Use the "Equation" button, below.

Bad news, though, you can achieve ONLY the decimal approximation.  Are you SURE it is written correctly?  Was there a problem statement along with this?

anonymous · Answer

Thanks I figured it out. You have to use the formula $$\log_{a}M+\log_{a}N=\log_{a}(MN)   $$ and solve from there.  Have a good night!  :)

tkhunny · Answer

Well, since that won't help the way it's written, I'm glad you managed to solve it, anyway.

anonymous · Answer

maybe you need to familiarize yourself with the formula.  What I wrote is verbatim.  I used the formula and didn't have a problem solving it.  It's written correctly and had you tried to solve it before responding you would probably know that.  Consequently I'm glad I solved it...... on my own.

tkhunny · Answer

Nope, sorry.  It can't be done as written.  If it should be this: $$\log_{8}(x+6)+\log_{8}(x+3) = 2$$ that would be en entirely different story.  If that other "log" actually is not in the problem statement, and the formula you suggested resulted in a "correct" solution, then the solution is wrong or the problem statement is wrong.  It can't be neither.

anonymous · Answer

You are correct!  I did not type the other 'log'!  Sorry for the confusion and my frustration.  Thank you for your help and patience.  Have a great day!  (Maybe you'll get to help me again soon)

tkhunny · Answer

I feel much better.  I just didn't want you wandering off with some crazy idea...  :-)