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Physics 9 Online
OpenStudy (anonymous):

Physics help with friction! the problem is "You push a 25kg wooden box across a wooden floor at a constant velocity of 1.0 m/s. If the coefficient of friction is .20, how much force do you exert on the box?"

OpenStudy (anonymous):

how do you set up the question?

OpenStudy (anonymous):

I know that m= 25kg

OpenStudy (anonymous):

F=\[nuN\]

OpenStudy (anonymous):

First, you draw the free body diagram. And note that the question tells you: there is no acceleration(constant velocity) Then you apply Newton's second law to it.

OpenStudy (anonymous):

ok so newtons second law you would use f=ma?

OpenStudy (anonymous):

yes. \(\Sigma F = m\Sigma a\)

OpenStudy (anonymous):

oh ok a

OpenStudy (anonymous):

so we know that m=25 kg and what is the a?

OpenStudy (anonymous):

|dw:1352779234119:dw|

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