Question

solve by using the properties of rational exponents:
(a^-1/3 b^1/2) (a^-1/2 b^3/5)^10

Answer 1

ok... so use the power of a power in the 2nd set of brackets

\[(x^a)^b = x^{a \times b}\]

so it becomes

\[a^{-\frac{1}{3}}b^{\frac{1}{2}} \times a^{-\frac{1}{2} \times 10}b^{\frac{3}{5} \times 10}\]

once you have that sorted you need to use the multiplication law for same base\[x^a \times x^b = x^{a + b}\]

hope this helps.