Ask your own question, for FREE!
Mathematics 17 Online
OpenStudy (anonymous):

Describe the vertical asymptote(s) and hole(s) for the graph of posting pic

OpenStudy (anonymous):

OpenStudy (anonymous):

Do you know how to find the vertical asymptotes? and holes?

OpenStudy (anonymous):

not at all :(

OpenStudy (anonymous):

Ok so a vertical asymptote is where the denominator(bottom) equals zero. You're looking for what x value makes the denominator equal to 0. Right now the denominator is: \[x^2 - 10x + 21\] The answer isn't obvious. So you will need to factor this. Now what two numbers multiply together to make 21 and add together to make 10?

OpenStudy (anonymous):

A. asymptote: x = 5 and hole: x = 1?

OpenStudy (anonymous):

@KeemoD143 I don't think so

OpenStudy (campbell_st):

if you let x^2 - 10 + 21 = 0 and solve (factorising is easy) then the solutions will be the vertical asymptotes

OpenStudy (anonymous):

@campbell_st: x^2 - 10x + 21 = 0 (you forgot an x)

OpenStudy (campbell_st):

its an interesting problem because if you expand the numerator and then cancel you'll get 1 there will be points of discontinuity where the asymptotes would have been oops sorry for forgetting x

OpenStudy (anonymous):

woe i missed alot lemme see here

OpenStudy (anonymous):

asymptote: x = –5 and hole: x = –1

OpenStudy (anonymous):

nope. were you able to factor the denominator?

OpenStudy (anonymous):

no asymptote: x = –3 and hole: x = 5

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!