Question

Solve for x:
1) 4^2x-1=8^x
2) 27^2x-1=9^-x
3) (x+5)(3x-2)(23x)=0

Answer 1

for 1 and 2:

whenever you have x^a = x^b, you know that a = b

In Q1: try converting 4 and 8 into 2^2 and 2^3 and see if you can do it.

Answer 2

rewrite question 1 with the same base.... 2

\[(2^2)^{2x -1} = (2^3)^x\]

apply the appropriate index law than then equate the powers.