Question

Write the equation of the tangent line to the curve y = ln (2/e^2x) at the point (0, ln2).

Answer 1

it is really
\[\ln(\frac{2}{e^2})\]??

Answer 2

heh.

Answer 3

it's a line... so I doubt it.

Answer 4

\[\ln(\frac{2}{e^{2x}})\] right?

Answer 5

it is a line

Answer 6

\[\ln(\frac{2}{e^{2x}})=\ln(2)-\ln(e^{2x})=\ln(2)-2x\]

Answer 7

line with slope \(-2\) and \(y\) intercept \(\ln(2)\) so whatever you do , do not use any calculus

Answer 8

This!