Question

use the root test to determine if series converges or diverges:
sum(x=1->infinity) [((n!)^2n)/((2n)!)^n]

Answer 1

\[\sum_{1}^{\infty} (n!)^{2n}/((2n)!)^{n}\]

Answer 2

realise that if you divide both by (n!)^n, you will get a multiplication of n fractions, each less than 1/2.

Answer 3

sorry but why would i do that? i'm supposed to use the root test which gives me
(n!)^2/(2n)!
I just don't know how to go from here