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How to simplify this?
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\[y-2\sqrt{3}=\frac{\sqrt{3}+1}{\sqrt{3}-1} (x-2)\]
@ DLS y - 2sqrt(3) = {sqrt(3) + 1 / sqrt(3) - 1}* (x-2) in the second step , we are going to multiply the numerator and denominator by sqrt(3) + 1 y - 2 sqrt(3) = {sqrt(3) + 1}^2 / {sqrt(3)}^2 - (1)^2} * (x-2)
@DLS y - 2sqrt(3) = (3+1+2sqrt(3))/(3-1) * (x-2) after this step we need to solve above and we will get the required answer
@DLS right??????????/
y-2sqrt{3}=sqrt{3}+1/sqrt{3}-1(x-2) after rationalization ofsqrt{3}-1\]
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\[y-2\sqrt{3}=(\sqrt{3}+1)^{2}/2(x-2) finally solve y=(2+\sqrt{3})x-4\]
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