Question

What are the coordinates of the x-intercepts of the graph of y = 2x2 + 6x – 20? HELLPP! I am so incredibly confused!

Answer 1

y = 2x^2 + 6x - 20 -- set y equal to zero
0 = 2x^2 + 6x - 20
= 2 (x^2 + 6x - 20) --- 2 cannot equal zero so..
x^2 + 6x - 20 = 0
( x - 2 ) ( x + 5 ) = 0
x - 2 = 0 --> x=2
x + 5 = 0 --> x=-5

plug into original equation to find the y intercepts
x=2:
y = 2(2)^2 + 6(2) -20 = 0

x=-5:
y = 2(-5)^2 + 6(-5) -20 = 0

coordinates for x-intercepts
(2,0) and (-5,0)

Answer 2

Thank you so much this is perfect Cx