Use the quadratic formula to solve the equation?
4x2 – 6x – 10 = 0 is anybody able to show me work?

Question

Use the quadratic formula to solve the equation?
4x2 – 6x – 10 = 0  is anybody able to show me work?

anonymous · Answer

the quadratic formula is -b (±)Sqrt[b-4ac]/2a$$-b \pm \frac{ \sqrt{b-4ac}}{ 2a}$$

anonymous · Answer

where  

ax^2  +bx +c

just substitute and you will get your answer.

jim_thompson5910 · Answer

$$\Large x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}$$


$$\Large x = \frac{-(-6)\pm\sqrt{(-6)^2-4(4)(-10)}}{2(4)}$$


$$\Large x = \frac{6\pm\sqrt{36-(-160)}}{8}$$


I'll let you finish.

anonymous · Answer

I have all that work! I just get confused with the last part? like would i subtract 36-(-160)

anonymous · Answer

36--160?

well double negative is positive, 

so?

36+160

jim_thompson5910 · Answer

36-(-160) is the same as 36+160

anonymous · Answer

so it would become 196?

jim_thompson5910 · Answer

it would

anonymous · Answer

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