Question

Use the quadratic formula to solve the equation?
4x2 – 6x – 10 = 0 is anybody able to show me work?

Answer 1

the quadratic formula is -b (±)Sqrt[b-4ac]/2a\[-b \pm \frac{ \sqrt{b-4ac}}{ 2a}\]

Answer 2

where

ax^2 +bx +c

just substitute and you will get your answer.

Answer 3

\[\Large x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\]


\[\Large x = \frac{-(-6)\pm\sqrt{(-6)^2-4(4)(-10)}}{2(4)}\]


\[\Large x = \frac{6\pm\sqrt{36-(-160)}}{8}\]


I'll let you finish.

Answer 4

I have all that work! I just get confused with the last part? like would i subtract 36-(-160)

Answer 5

36--160?

well double negative is positive,

so?

36+160

Answer 6

36-(-160) is the same as 36+160

Answer 7

so it would become 196?

Answer 8

it would