functions:
If f(x)=x^2-x+1, solve:
1) f(x+1)
2) f(-a)
3) 2f(x)-2
4) f(2x)

Question

functions:
If f(x)=x^2-x+1, solve:
1)      f(x+1)
2)      f(-a)
3)       2f(x)-2
4)      f(2x)

anonymous · Answer

CAN I post my answers and someone check it?

anonymous · Answer

you mean "evaluate"?

anonymous · Answer

probably, sorry

anonymous · Answer

yeah, lol, just substitute whatever is in f(whatever is in here)

anonymous · Answer

yes i'll check it

anonymous · Answer

1)   x^2+x+3
2)    -a^2+a+1 (i didn't know if there was any way to simplify this?
3)    2x^2-x
4) 2x^2-2x+1

anonymous · Answer

all wrong, it three right 2 f(x)-2?

anonymous · Answer

its 2*f(x) -2

anonymous · Answer

can you show me how to do them then?

anonymous · Answer

yes

anonymous · Answer

jaersyn i got this

anonymous · Answer

all yours kmalone99

anonymous · Answer

<_<

anonymous · Answer

$$1) f(x+1)= (x+1)^{2}-(x+1)+1$$
$$=(x+1)(x+1)-x-1+1$$
$$=x ^{2}+2x+1-x=x ^{2}+x+1$$

anonymous · Answer

Ok, I get #1. I just didn't distribute the negative sign.

anonymous · Answer

2) f(-a)=$$f(-a)=(-a)^{2}-(-a)+1=a ^{2}+a+1$$

anonymous · Answer

now retry 3 and 4

anonymous · Answer

i got 2... i dont see what went wrong with 3 and i dont know how to simplify 4

anonymous · Answer

wait- 3 should be 2x^2-2x?

anonymous · Answer

great now on four you just did not square the 2

anonymous · Answer

oh! so it would be 4x^2-2x+1  ?

anonymous · Answer

yes great job you get A+

anonymous · Answer

yay! lol I just always make silly simplifying mistakes or I miss a sign or something simple like that. Oh well, thanks very much ^_^