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Solve square root of 2x + 1 = x + 1 for x. a. No Solution b.±2 c.±3 d.0
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Is the square root over the 2x only? like this\[\sqrt{2x}\] or is the 1 under the squre root also?
the one is under the square root too
There is a trick to get rid of the radical or 'square root'; do you know how to do that?
No not too shabby with math
There is a law \[(\sqrt{a})^{2}=a\] if you square a square root, it becomes that thing inside the square root. You can square both sides of your equation.
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And the answer is?
square both sides and solve it
\[\sqrt{2x+1}=x+1\] \[(\sqrt{2x+1})^{2}= (x+1)^{2}\]
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