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you need to plot these points with graph paper and see
ok
I was thinkin b?
sorry my answer was not helpful, i saw it as i plotted the points
no that is not it you need to compute the slope of AB and of AC do you know how to do that?
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idk ..
A is \((-2,4)\) and B is \((6,0)\) slope is \[\frac{y_2-y_1}{x_2-x_1}\] in whatever order you choose you get \[\frac{0-4}{6-(-2)}=\frac{4}{-8}=-\frac{1}{2}\]
actually it was \[\frac{-4}{8}=-\frac{1}{2}\]
slope of AC A is \((-2,4)\) and C is \((-4,0)\) slope is \[\frac{4-0}{-2-(-4)}=\frac{4}{2}=2\]
since \(-\frac{1}{2}\) is the negative reciprocal of \(2\) you know AB and AC are perpendicular
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so...a?
I mean c
no AB is perpendicular to AC
yes C it is always C
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