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Mathematics 11 Online
OpenStudy (anonymous):

help?!?!

OpenStudy (anonymous):

you need to plot these points with graph paper and see

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

I was thinkin b?

OpenStudy (anonymous):

sorry my answer was not helpful, i saw it as i plotted the points

OpenStudy (anonymous):

no that is not it you need to compute the slope of AB and of AC do you know how to do that?

OpenStudy (anonymous):

idk ..

OpenStudy (anonymous):

A is \((-2,4)\) and B is \((6,0)\) slope is \[\frac{y_2-y_1}{x_2-x_1}\] in whatever order you choose you get \[\frac{0-4}{6-(-2)}=\frac{4}{-8}=-\frac{1}{2}\]

OpenStudy (anonymous):

actually it was \[\frac{-4}{8}=-\frac{1}{2}\]

OpenStudy (anonymous):

slope of AC A is \((-2,4)\) and C is \((-4,0)\) slope is \[\frac{4-0}{-2-(-4)}=\frac{4}{2}=2\]

OpenStudy (anonymous):

since \(-\frac{1}{2}\) is the negative reciprocal of \(2\) you know AB and AC are perpendicular

OpenStudy (anonymous):

so...a?

OpenStudy (anonymous):

I mean c

OpenStudy (anonymous):

no AB is perpendicular to AC

OpenStudy (anonymous):

yes C it is always C

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