Rewrite y''+y'+y=0 as a system of first order differential equations. Find the eigenvalues and eigenvectors of the system.
\[\lambda^{2} + \lambda + 1 =0\] solve it
Is it \[\lambda= +/- \sqrt{-3/4}-1/2 \] ?
correct those are the eigenvalues \[-\frac{ 1 }{ 2 }\pm \frac{ i \sqrt{3} }{ 2 }\] can you put them in sin and cos form to get the eigenvectors
I'm not sure, could you walk me through it?
are the sin and cos forms \[e ^{-1/2t}(\cos \sqrt{3}/2t + i \sin \sqrt{3/2}t)\] and \[e ^{-1/2t}(\cos \sqrt{3}/2t - i \sin \sqrt{3/2}t)\] ?
\[y(t) = e^{-1/2t}(c1*\cos(\sqrt{3}/2)+c2*\sin(\sqrt{3}/2))\]
ok, i think I see that
Is y(t) our eigenvector here?
yup site is too slow!
lol, I had to wait an hour earlier this morning to get on. Thanks for your help, I really appreciate it :)
no problem. btw are you engineer?
yes, mechanical. I'm a 3rd year.
im electrical :)
cool :) what year? or have you graduated already?
my 2nd yr in masters
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