Question

Solve. sin^3x+sinx*sin2x-cos^3x=0

Answer 1

You'll need a common angle between all the trig functions. what makes the most sense:
x, 2x, or 3x?

Answer 2

Probably x.

Answer 3

It's sin^3(x) not sin3x.

Answer 4

\[\huge{\sin^3x+sinx*\sin2x - \cos^3x} ?\]

Answer 5

Exactly. :)

Answer 6

You'll still have to break the sin2x into some combination of sinx with half angle identity

Answer 7

Thought of that too, I'll try and see what happens. Thank you for the idea!