Question

Problem solving

Answer 1

@tiawanad

16a^2/4a+11b minus 121b^2/4a+11b
\[\frac{ 16a^{2} }{ 4a + 11b } - \frac{ 121b^{2} }{ 4a + 11b }\]
\[\frac{ 16a^{2} - 121b^{2} }{ 4a + 11b }\]
\[\frac{ ( 4a + 11b ) ( 4a - 11b ) }{ 4a + 11b }\]
\[4a + 11b\]

Answer 2

i'm sorry.., i mean
the answer is

\[4a - 11b\]

Answer 3

yeah I got that one right

Answer 4

ok.., great!!

Answer 5

now I am trying to find the lcm for this one x^2+4x, x^2-4x please help me

Answer 6

what do u mean by "lcm" ????

Answer 7

would it be x^2(x-4x)

Answer 8

@tiawanad what do u mean by "lcm" ??

Answer 9

x^2+4x, x^2-4x
x^2(1 + 4/x), x^2 (1- 4/x)

Answer 10

i got 4x^2(x+2)(x-2)

Answer 11

2y/y(3y-1) + 3/3y-1
\[\frac{ 2y }{ y(3y -1)} + \frac{ 3 }{ (3y -1 )}\]
\[\frac{ 2y + 3y }{ y(3y -1)}\]
\[\frac{ 5y }{ y(3y - 1)}\]
\[\frac{ 5 }{ (3y - 1)}\]

@tiawanad

Answer 12

2/1-x=7/1+x

\[\frac{ 2 }{ 1 - x } = \frac{ 7 }{ 1 + x }\]
2 (1+x) = 7 ( 1-x)

2 + 2x = 7 - 7x
2x + 7x = 7 - 2
9x = 5
x = 5/9

Answer 13

@tiawanad