Question

find all the zeros of the equation: x^4-6x^2-7x-6=0

Answer 1

do u know how toreduce biquadratic to a quadratic form ...

Answer 2

no

Answer 3

otherwise clearly 3 is one of the zeroes of the equ. by factor and remainder theorem so divede the equation by x-3 and the find the zeroes of the cubic quotient again

Answer 4

-2

Answer 5

after division the cubic obtained is x^3 +3x^2 +3x+2
yes -2 is another factor
so divide the cubic by x+2 again to obtain the quadratic

Answer 6

after division the quadratic so obtained is x^2 +x+1

Answer 7

the roots of the quadratic is (-1+-sqrt(3)i)/2 [ i is sqrt(-1)]
thus the roots are -2,3 and (-1+-sqrt(3)i)/2