Question

I don't understand how 3x^2-18x+26 is figured out. The question will uploaded...

Answer 1

Yes. Factoring the equation will give you basically two functions both equal to 0. So you can find the answers.

I'm not sure how that the equation in the question matches the uploaded document.

Answer 2

Oh. Okay. They gave you:

\[f(x)=a(x-3)^{2}-1\]

Now we know that a = 3 so:

You can get \[f(x)=3(x-3)^{2}-1\]

Know then: (x-3)(x-3)=x^2-6x+9 by factoring.

If you then multiply that times 3 and subtract 1 you get the answer.

This is about plugging in a variable, factoring, and solving.

Answer 3

it is uploaded

Answer 4

I am trying to figure out how the final answer is figured out.

Answer 5

I did it in the above. You take the a and make it a 3, then factor, and then simplify. Do you need help factoring or figuring out the other parts?

Answer 6

um how did you get x^2-6x+9?

Answer 7

Okay:

(x-3)(x-3)

Multiply the first times the first
First times the second
Second times the first
Second times the second.

1) x times x = x^2
2) x times (-3) = -3x
3) (-3) times x = -3x
4) (-3)(-3) = 9

Next you add all of those parts up to get :

x^2-3x-3x+9

The -3xs can go together to get:

x^2-6x+9

Answer 8

I see thanks.

Answer 9

It might seem confusing, but once you get the hang of it you'll be able to do them in your head pretty fast.