What are the factors of 3x^2 + 13x + 4
Polynomials are factored by their roots. That is, when f(x) = 0, the values of x can be used to factor the polynomial.
To find the root of a quadratic equation in the form of \(ax^2+bx+c\), it's easiest to use the quadratic equation to find the roots.
Once you have found the roots, the polynomial is factored as \((x-r_1)(x-r_2)=0\).
So if the roots are 1 and -2, then it's factored as \((x-1)(x+2)\)
????? i dont get it
there are multiple ways to factor a polynomial
what method are you supposed to use?
Hint: 3*4=12 1*12=12 1+12=13.
Do you know how to do factor-by-grouping? \( 3x^2 + 13x + 4 = 3x^2+12x+x+4\)
no i dont understand it
Factoring a quadratic trinomial is the reverse of multiplying linear binomials using the FOIL method (First Outer Inner Last)
If you multiply something like (x+3(2x-2), you get 2x^2 -2x +6x -6. After combining like terms, you'll have the trinomial, 2x^2+4x-6. You can see that if you do it in reverse, you can find two numbers that multiply to make 12 (2*6), that add to make 4.
(1x+4)(3x+1) =3x^2+1x+12x+4= 3x^2+13x+4
Join our real-time social learning platform and learn together with your friends!