Question

Write the equation of the line that is parallel to the line y = −3x + 12 and passes through the point (−1, 6).

y = x + 7

y = −3x + 3

y = x + 3

y = −3x + 7

Answer 1

What do you know about the new line?

Parallel lines have the same slope. You also have a given point.
Slope -3
Point (−1, 6)

Use Point-Slope form.
\[y - y1 = m(x - x1) \]y - 6 = -3(x - (-1))
y - 6 = -3(x + 1)
\[Distribute\]y - 6 = -3x - 3
\[Add\quad 6\]y = -3x + 3

Answer 2

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