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k=1/3(b-2a) solve for b would you use the distributive property first or divide both sides by 1/3?
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K =1/3 (b – 2a) 3K = (b – 2a) 3K + 2a = b b = 3K + 2a
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Why would you divide 1/3 before you would use the distributive property?
since 1/3 is only on one side u can move it or divide and the result will bee the same 3k=b-2a and b=3k+2a
\[k=\frac{ 1 }{ 3 }*(b-2a)| *3 <=> 3k=b-2a <=> b=3k+2a\]
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