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Mathematics 13 Online
OpenStudy (anonymous):

Consider the following statement: “All mathematicians must be good logicians and all good logicians must justify their claims.” a) Write this statement symbolically as a conjunction of two conditional statements. Use three components (p, q, and r) and explicitly state what these are in your work. Remember: a component in logic is a simple declarative sentence that is either true or false. b) Write the negation of this statement

OpenStudy (anonymous):

Okay, so suppose we have the form: "All p must be q". The question is does this mean \(p\implies q\) or \(q \implies p\)? You have to test it out a bit.

OpenStudy (anonymous):

So I'd start out with something like... "All dogs must be animals". Now does this mean "If you're a dog, then you're an animal." or does it mean "If you're an animal, you must be a dog"?

OpenStudy (anonymous):

@princesspixie Does this help?

OpenStudy (anonymous):

a little but what does a dis junction mean?

OpenStudy (anonymous):

Disjuntion isn't mentioned, but I'd assume it's two propositions combined with 'or'.

OpenStudy (anonymous):

oh i meant to say conjunction sorry!

OpenStudy (anonymous):

conjunction is when you take two propositions and combine them with and or or.

OpenStudy (anonymous):

but the sentence already has the word and in it so thats why im confused..

OpenStudy (anonymous):

Which just means you use and \( \wedge\) for it.

OpenStudy (anonymous):

??

OpenStudy (anonymous):

can you give me an example..

OpenStudy (anonymous):

this would be the first answer ? : “All mathematicians must be good logicians ^ good logicians must justify their claims.”

OpenStudy (anonymous):

No, because you need to convert them into conditionals.

OpenStudy (anonymous):

“if you are a mathematicians then you must be a good logician and all good logicians must justify their claims.” ??

OpenStudy (anonymous):

Yeah, now I'd say that \(p\) means 'person is mathematician' \(q\) means 'person is good logician' and \(r\) means 'justifies their claims'

OpenStudy (anonymous):

So we end up with \[ (p \implies q)\wedge(q \implies r) \]

OpenStudy (anonymous):

ok, is that part of the answer?

OpenStudy (anonymous):

That is part a.

OpenStudy (anonymous):

ok, great thanks! how would i negate it now? just throw a not in front of the original sentence?

OpenStudy (anonymous):

Yeah, throw in a \( \lnot \) .

ganeshie8 (ganeshie8):

and you may have to simplify

ganeshie8 (ganeshie8):

\( \neg ( ( p \implies q ) \wedge ( q \implies r ) ) \) \( \neg ( p \implies q ) \vee \neg ( q \implies r ) \) \( (p \wedge \neg q) \vee (q \wedge \neg r) \)

ganeshie8 (ganeshie8):

which means, the statement is true, whenever a 'mathematician is not a logician' or whenever a 'logician is not a justfier'

ganeshie8 (ganeshie8):

which forms a logical negation of the original statement

OpenStudy (anonymous):

ok thank you :)

ganeshie8 (ganeshie8):

np.. yw :)

OpenStudy (anonymous):

so should the negation be : a mathematician is not a good logicians and logicians do not justify claims ?

OpenStudy (anonymous):

needs to be an or in the middle

OpenStudy (anonymous):

so would it be : a mathematician is not a good logician or logicians would justify their claims?

OpenStudy (anonymous):

@wio

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