Question

Simplify

Answer 1

\[=\frac{ 4x^2+12=16 }{ 2x+10 }\times \frac{ x^2+9x+20 }{6x+24 }=\frac{ 4(x^2+3x-4) }{2(x+5 )}\times \frac{ (x+4)(x+5) }{ 6(x+4) }=\frac{ 4(x-1)(x+4) }{ 2(x+5) }\times \frac{ (x+4)(x+5) }{ 6(x+4) }=\frac{(x-1)(x+4) }{ 3 }\]

Answer 2

i can´t see the end of the equations :/

Answer 3

would the answer be \[\frac{ 3 }{ (x-1)(x+4) }\]

Answer 4

? @ASAAD123

Answer 5

inverse

Answer 6

((x-1)(x+4))/3

Answer 7

oh yeh sorry

Answer 8

thanks!