Question

how do you find the lcd of 1/(x^2-36),(x+3)/(7x^3-42x^2)

Answer 1

\[\frac{1}{(x^2-36)}=\frac{1}{(x+6)(x-6)}\]
\[\frac{ (x+3) }{ (7x^3-42x^2) }=\frac{ (x+3) }{ 7x^2(x-6) }\]

Answer 2

what will make the two fractions has the same denominator

Answer 3

@niho u there?

Answer 4

sorry..don't really know how this site works

Answer 5

idk how to do the problem

Answer 6

what will you multiply the 1st den. with to get a common den. with the 2nd one and what will you muliply the 2nd one with to get a common den

Answer 7

I really don't know.

Answer 8

\[\frac{1}{(x+6)(x-6)}*\frac{7x^2}{7x^2}=\frac{7x^2}{7x^2(x+6)(x-6)}\]
\[\frac{(x+3)}{7x^2(x -6)}*\frac{(x+6)}{(x+6)}=\frac{(x+3)(x+6)}{7x^2(x+6)(x-6)}\]

what is the common den?

Answer 9

7x^2(x+6)(x-6)

Answer 10

thats it

Answer 11

thankyou