Question

integrate : ( indefinite)
1 / sinx + secx

Answer 1

using
1/sinx + 1/cosx= cosx+sinx/sinx cosx
then using sum and product rule sinx cosx =1/2 sin(2x)+sin(0)

Answer 2

Its 1/sinx + secx or 1/(sinx +secx)??

Answer 3

Integrate each term separately to get
log(|cosec(x)-cotan(x)|+log(|tan(x)+sec(x)|)
If we assume the log arguments are positive and using the fact that log(a)+log(b)=log(a*b) we can transform this into
log(1/sin(x)-1/cos(x)/sin(x)-1/cos(x)+1)

I have attached an .xps (microsoft format) file with more details

Answer 4

1/(sinx +secx)