If C = {2, 4, 6, 8, 10, 12, 14, 16} and D = {numbers divisible by 4 from 1 to 20}, what is C ∩ D? {2, 4, 6, 8, 10, 12, 14, 16, 20} {4, 8, 12, 16, 20} { } {4, 8, 12, 16}
C intersects D is the meaning of the upside down horseshoe, so you find the what is the common numbers in both set.
C ∩ D is the set which contains all elements common to set C and D
so if list all elements in D you just need to compare the elements
so if list all elements in D you just need to compare the elements
So, if I put the numbers like this... 2 4 4 8 6 12 8 16 10 12 14 16 What is the common numbers in both sets?
no as 2 is not divisible by 4
i have to say that this question can be considered a bit misleading since it does not define the set of _______ numbers which it is expecting the solution to be in.
Lexijean123 what do u think?
4,8,12,16
yup
yup
Yep, you r right! Good job! Understand how to do this now?
yes !(:
Good job again, and good luck!
hmmm, i spose i have a less rigid definition of divisibility. having a remainder of 0 seems to be a commonplace in alot of the defintions of divisibilty
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