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Calculus1 19 Online
OpenStudy (anonymous):

f(x)=(2)/(x^2-9) Use interval notation to indicate where is increasing and decreasing

OpenStudy (anonymous):

Do you know how to take the derivative of a function?

OpenStudy (anonymous):

-(4x)/((x-3)^2(x+3)^2)

OpenStudy (anonymous):

Okay, now do you know how to find the second derivative?

OpenStudy (anonymous):

To find the inflection point, you find the second derivative, and set it equal to 0. Then solve.

OpenStudy (anonymous):

Yeah, (12(x^2+3))/((x^2-9)^3)

OpenStudy (anonymous):

There are no inflection points, I'm trying to find where f(x) is increasing and decreasing in interval notation.

OpenStudy (anonymous):

Give me a min to solve this.

OpenStudy (anonymous):

So, only 1 point which is 0. so the function is increasing from -infinity to 0 and decreasing from 0 to infinity.

OpenStudy (anonymous):

Instead of infinity.

OpenStudy (anonymous):

Sorry, increases from -3 to 0. and decreases from 0 to 3.

OpenStudy (anonymous):

Nope, that's not right.

OpenStudy (anonymous):

-3<=x<=0, and 0<=x<=3.

OpenStudy (anonymous):

It's like this -infinity<=x<-3 union -3<x<=0. Same goes for decreasing.

OpenStudy (anonymous):

I can't seem to write the decreasing one correctly... (INF,0)U(0,3)?

OpenStudy (anonymous):

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