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Calculus1
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OpenStudy (anonymous):
f(x)=(2)/(x^2-9)
Use interval notation to indicate where is increasing and decreasing
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OpenStudy (anonymous):
Do you know how to take the derivative of a function?
OpenStudy (anonymous):
-(4x)/((x-3)^2(x+3)^2)
OpenStudy (anonymous):
Okay, now do you know how to find the second derivative?
OpenStudy (anonymous):
To find the inflection point, you find the second derivative, and set it equal to 0. Then solve.
OpenStudy (anonymous):
Yeah,
(12(x^2+3))/((x^2-9)^3)
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OpenStudy (anonymous):
There are no inflection points, I'm trying to find where f(x) is increasing and decreasing in interval notation.
OpenStudy (anonymous):
Give me a min to solve this.
OpenStudy (anonymous):
So, only 1 point which is 0. so the function is increasing from -infinity to 0 and decreasing from 0 to infinity.
OpenStudy (anonymous):
Instead of infinity.
OpenStudy (anonymous):
Sorry, increases from -3 to 0. and decreases from 0 to 3.
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OpenStudy (anonymous):
Nope, that's not right.
OpenStudy (anonymous):
-3<=x<=0, and 0<=x<=3.
OpenStudy (anonymous):
It's like this -infinity<=x<-3 union -3<x<=0. Same goes for decreasing.
OpenStudy (anonymous):
I can't seem to write the decreasing one correctly...
(INF,0)U(0,3)?
OpenStudy (anonymous):
|dw:1353362319074:dw|
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