Question

What is the slope and y-intercept of the graph of 3x + 2y = 12?

Answer 1

Change this in the form y= mx + c

m = slope

c = y intercept

Answer 2

go from \(Ax+By=C\) to \(y=mx+b\)
to do that all you have to do is get \(y\) alone on one side:\[3x+2y=12\]subtract the \(3x\):\[2y=-3x+12\]divide both sides by \(2\):\[y=-{3\over2}+6\]so from that we can conclude that the slope is \(m=\large-{3\over2}\) and the y intercept is \(b=6\)
hope this helps! :) @Hiamsam

Answer 3

Thanks guys!

Answer 4

One more question.@yummydum

Answer 5

Can you help me on this?
http://gyazo.com/7f093791002c8c33808848ad12b0db10
(screenshot)

Answer 6

k sure

Answer 7

\(\huge{6x+24\over6}\) \(\implies\) \(\huge{{6x\over6}+{24\over6}}\)

so now we just simplify and get \(\implies~~~~\huge{x+4}\)

Answer 8

Thanks! again! XD

Answer 9

no problem man!

Answer 10

{(96, 80), (114, 95), (132, 80), (96, 95), (114, 120)}

What is the difference between the values of the least and greatest elements in the domain of this relation?

Answer 11

im not sure about this one but i guess you just subtract the lowest value from the highest value:\[~~~(114~,~120)\]\[\underline{-~(96~~,~~80)}\]\[~~~~(18~~,~~40)\] so i guess the answer would be \(\large(18,40)\)

Answer 12

18 or 40?
It only has one choice :x

Answer 13

OH wait this is domain....so that means the lowest x value subtracted from the highest x value:\[\large132-96=36\]

Answer 14

thanks =p

Answer 15

whenever it says \(\text{domain}\) its talking about \(x\) and whenever it says \(\text{range}\) its talking about \(y\)

Answer 16

Got it!

Answer 17

cool :)

Answer 18

Just to check
is this right? http://gyazo.com/c424840d6aa38bb7e40cb20fe660fab3

Answer 19

\[3x-4y=12\]subtract \(3x\):\[-4y=-3x+12\]divide by \(-4\):\[y={3\over4}x-3\]so to find the x-intercet we put \(0\) in for \(y\):\[3x-4(0)=12\]simplify:\[3x=12\]divide by \(3\):\[x=4\]
so the intercept is \((4,0)\) and the y intercept is \((0,-3)\)
Option \(\text{B}\)

Answer 20

Thanks, again! Lol. :)

Answer 21

yup