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How do you solve the following two equations by factoring? 1) x² - 2x - 15 = 0 2) 2x² - 3x + 1 = 0 Thank you :)
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You can use the quadratic formula when you get you X's turn them into factors. Do you understand or do you need me to show you?
Well I'm struggling so I'd like you to show me please. :) @kelsey1
\[x^2 - 2x - 15 = 0\] This factors into \[(x-5)(x+3) = 0\]. So \[x=5\] or \[x=-3\]
okay no problem I'll show you the steps!
Awesome thank you very much! I was stuck on the factoring part. @rsnoob Any ideas for the second equation? @kelsey1
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1. \[2x2 -3x + 1 = 0\] 2. \[2x2 - 2x - x + 1 = 0\] 3. \[2x(x-1)-1(x-1)=0\] 4.\[( 2x-1) (x-1 ) = 0\] 5. \[X = 1/2\] or \[x=1\]
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