Mathematics
14 Online
OpenStudy (anonymous):
Find the volume of a regular tetrahedron whose altitude measures 10 cm.
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hartnn (hartnn):
the formula is
V = \(\sqrt 2\)/12 * a^3
OpenStudy (anonymous):
it is not the edge that is given but the ALTITUDE..
OpenStudy (anonymous):
now i got it.. :))
OpenStudy (anonymous):
How ?
OpenStudy (anonymous):
altitude = root(2/3) * a
10 = root(2/3) * a
100=2/3 a^2
a= 5 root 6
V = root(2)/12 * a^3
V = 216.5
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OpenStudy (anonymous):
I thought it like this..\[\large\color{green}{x=\frac{100}{\sqrt{3}}}\]
|dw:1353600894733:dw|
OpenStudy (anonymous):
Sorry..\[\large\color{green}{x=\frac{10}{\sqrt{3}}}\]
OpenStudy (anonymous):
that's fine.. ^^
OpenStudy (anonymous):
;)
OpenStudy (anonymous):
@eroshea I am glad tht u got it..:D :)
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OpenStudy (anonymous):
thanks for your help @hartnn and @Miyuru ^^
OpenStudy (anonymous):
I didn't help.. o.O
OpenStudy (anonymous):
Thank @hartnn ONLY
OpenStudy (anonymous):
well, you tried helping me.. so thanks :))
hartnn (hartnn):
u got it on your own, @eroshea :)
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OpenStudy (anonymous):
Is my way wrong @hartnn
hartnn (hartnn):
if u got the same volume, then u are correct.
OpenStudy (anonymous):
It's nearly 181.4 :(
hartnn (hartnn):
then incorrect :P
OpenStudy (anonymous):
:D
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OpenStudy (anonymous):
:D
OpenStudy (anonymous):
OHH Anyway thnks for U all and Welcome...
OpenStudy (anonymous):
Ohh @eroshea you mean the height is 10.. Isn't it ?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
I thought it was the altitude of a triangle.. :P
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OpenStudy (anonymous):
no.. it's the height of the tetrahedron
OpenStudy (anonymous):
Ok got it.. :) Then your way is correct. :D
OpenStudy (anonymous):
yep :D
OpenStudy (anonymous):
what is the figure and where did 2/3 came from?