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Mathematics 24 Online
OpenStudy (anonymous):

A circle is shown on the coordinate plane below. What is the equation of this circle?

OpenStudy (anonymous):

OpenStudy (anonymous):

x2 + (y + 1)2 = 4 x2 + (y – 1)2 = 2 x2 + (y + 1)2 = 2 x2 + (y – 1)2 = 4

OpenStudy (anonymous):

anyone help me please?

OpenStudy (cwrw238):

just compare them to the general equation of circle in your last post

OpenStudy (anonymous):

answer is c?

OpenStudy (cwrw238):

no - what is radius of the circle? - check the diagram

OpenStudy (anonymous):

radius is 1 correct?

OpenStudy (cwrw238):

the radius is he distance from the centre of the circle to a point on the circle, can you find the coordinates of the centre?

OpenStudy (anonymous):

0,1 right?

OpenStudy (anonymous):

hello are you there?

OpenStudy (sirm3d):

yes, it is at (0, 1).

OpenStudy (anonymous):

so whats my answer?

OpenStudy (anonymous):

B?

OpenStudy (sirm3d):

do you know a point on the circle that has known coordinates? if yes, what is its distance from the center C(0,1)?

OpenStudy (anonymous):

is the answer x2 + (y – 1)2 = 2

OpenStudy (anonymous):

my choices are above

OpenStudy (sirm3d):

the center is at (0,1) so the equation of the circle is \[\large (x-0)^2 + (y-(-1))^2=r^2\] that leaves you two choices A or C. you need to compute the radius of the circle.

OpenStudy (anonymous):

A

OpenStudy (sirm3d):

A it is. a point on the circle is (0,3). so the radius is 2

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