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OpenStudy (anonymous):
Integrate (dx/xlnx)???
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OpenStudy (zzr0ck3r):
????????????/
OpenStudy (zzr0ck3r):
= d/lnx
OpenStudy (anonymous):
\[\int \frac{dx}{xlnx}\]?
OpenStudy (anonymous):
Hint: u substitute for ln(x)
OpenStudy (anonymous):
yes.. How to integrate that @Omniscience
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OpenStudy (anonymous):
u = lnx => du/dx = 1/x
OpenStudy (zzr0ck3r):
this makes no since, please repost
OpenStudy (anonymous):
no sense?
OpenStudy (zzr0ck3r):
sense*
OpenStudy (anonymous):
u = ln(x)
du = 1/x dx
We can replace that in the integral equation
\[\int\limits_{}^{}\frac{ 1 }{ u }du\]
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OpenStudy (anonymous):
u takes the place of ln(x) and du takes the place of dx/x. YOu are still left with u in the denominator tho be careful
OpenStudy (zzr0ck3r):
what is dx/x?
OpenStudy (anonymous):
1/x dx
OpenStudy (anonymous):
a different way to write it
OpenStudy (zzr0ck3r):
o lil thought it was a typo sorry
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OpenStudy (anonymous):
can you do the problem now?
OpenStudy (anonymous):
ok.. I got it u=ln x
then du/dx=1/x
so xdu=dx
substitute the value
it will be Integrate of du/u so the last answer is ln(lnx)
it is correct???
OpenStudy (anonymous):
Ya thats correct. I've never seen u substitution setup quite like that but if it works in your head then more power to ya
OpenStudy (anonymous):
Thank all for helping.>>
OpenStudy (zzr0ck3r):
sorry Ive been drinking rum:)
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