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OpenStudy (hba):
What is the question ?
OpenStudy (anonymous):
Determine the domain of each function
OpenStudy (nubeer):
all real numbers except x = 0
OpenStudy (anonymous):
So I substitute x to 0
OpenStudy (nubeer):
when u put x =0 u will gget infinity
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OpenStudy (nubeer):
so all real numbers are domain but\[x \neq0\]
OpenStudy (anonymous):
It's just 0??
OpenStudy (nubeer):
no.. just not 0.. except 0 every number is in the domain
OpenStudy (anonymous):
So it's 3/5
OpenStudy (nubeer):
do you know what domain is?
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OpenStudy (anonymous):
It's then x value right
OpenStudy (nubeer):
domain is the possible values of x for which you can get some definite answer..
OpenStudy (nubeer):
so all real number means
1,-1,2,-2,3,-3 and so on .. just not 0
because when u put 0 u will get infinity so 0 not included. so every number in arithmetic is in the domain of this equation except 0
OpenStudy (anonymous):
But negative numbers aren't real numbers or are they...
OpenStudy (nubeer):
i think they are.
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OpenStudy (anonymous):
Ok so wat do I do
OpenStudy (hba):
@nubeer are you helping jay ?
OpenStudy (anonymous):
I don't get this
OpenStudy (nubeer):
yes i am trying if u can see..
u can write all real numbers \[x \neq0\]
or
\[[-\infty , 0) (0,\infty]\]
OpenStudy (anonymous):
Oh ok that makes sense
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OpenStudy (anonymous):
Thank you
OpenStudy (nubeer):
you are welcome.
OpenStudy (anonymous):
3/x+5= f(x)
we knw 3/0 is not defined...so
x + 5 not equal 0
x not equal 5
so...Domian = R-{5}