Ask
your own question, for FREE!
Mathematics
18 Online
OpenStudy (anonymous):
The sides of an isosceles triangle have lengths 3x-1, -2x+29. The base has length 4x+5. What is the length of the base?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
help please!
jimthompson5910 (jim_thompson5910):
|dw:1353702112988:dw|
jimthompson5910 (jim_thompson5910):
|dw:1353702129485:dw|
jimthompson5910 (jim_thompson5910):
the congruent legs are 3x-1 and -2x+29
jimthompson5910 (jim_thompson5910):
so
3x-1 = -2x+29
solve this for x
Join the QuestionCove community and study together with friends!
Sign Up
jimthompson5910 (jim_thompson5910):
once you have x, use it to find 4x+5
OpenStudy (anonymous):
That's how i thought you solve it, but each time i try to solve for x i get 3x=28 but if you divide28 by 3 you get a decimal, what am i doing wrong?
jimthompson5910 (jim_thompson5910):
3x-1 = -2x+29
3x-1+2x = -2x+29 +2x
3x+2x -1 = 29
3x+2x -1+1 = 29+1
3x+2x = 29+1
I'm sure you see where you went wrong at this point
OpenStudy (anonymous):
i see where i went wrong i forgot to write the x on -2 so the answer is 29(:
jimthompson5910 (jim_thompson5910):
yes because x = 6
base = 4x+5
base = 4*6 + 5
base = 24+5
base = 29 units
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
thanks for helping!
jimthompson5910 (jim_thompson5910):
np
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!