i neeed help!!!!! Solve the trigonometric equation.. sinx tan^2x=sinx
your real name is shelly poop?
no. its shelly.
then why poop? o.O
i just randomly made up a username
quite some name that is! o.O
anyways,,for the question,,bring everything in LHS..what do you get?
thanks . haha LHS?? whats that?
left hand side :P
i know i have to equal it to zero , i think , or put it all on one side?
ohhh haha i knew that >.<
yep./..put all on one side..
now take sinx common out..what do you get ?
\[sinx \tan^2x=sinx .\] That's the question, no?
yeahh thats the question .. i dont make tan^2 to 1-sec^2x ??
i think that is not required, if u know when tan x =0 first, bring all terms on one side, what u get ?
you get sinx tan^2x -sinx .. then the sin cancels out? nd tan^2x=0 ?
its not accurate to say that sin cancels out you factor out sin x like this : sinx (tan^2x-1) = 0 then u equate both factors to 0.
oohh okay thank you very much!:]
so , can u solve for x in sinx (tan^2x-1) = 0 ?
umm i think.. haha ill try to figure it out >.<
sure, if u don't get it, ask....
do i move the 2 in front of the tan? haha. >.<
sinx (tan^2x-1) = 0 equating both factors to 0, u get sin x=0 tan^2 x = 1 right ?
yeaaahh
so what is x, when sin x=0 ??
pi and 2pi ,, sorry i dont have the little symbol
yeah, do u have any interval to solve in ?? or u want general solution ??
general
so, starting with 0, sin x is 0 for x=0,\(\pi\),2\(\pi\),3\(\pi\),........n\(\pi\) got this ?
yeah i understand that part ,
the tan part i dont get
\(\tan^2x = 1\) so, tan x = \(\pm\)1 right ? u know for which values of x are tan values + or -1
what happened to the ^2 ?
taking square root on both sides....
ohhhhhhh you squared it! . ahh i feel so dumb-.- , ahh yess thank you so much!! i know the values now :] .
great :) welcome ^_^
thanks again!!:D
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