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What is the answer to this square root problem?
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\[4\sqrt{7x}-7\]
What's the question?
It's up above, do you see it or should I write it again?
I see an algebraic radical expression, but I don't know what you want to do with it.
I need to know how to solve it
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Going to need an equals sign somewhere if you hope to solve anything.
Hmm, I accidentally cut out part of the problem... hold on one sec
\[2\sqrt{7x}+\sqrt{7x}-3\sqrt{7x}-7\]
There, that's the whole problem :)
There is still no equals sign, so there is nothing to solve for. The expression as is simplifiies to -7 since all the other terms cancel out.
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