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sqrt(x+2)+4=x can anyone help?
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\[\sqrt{x+2}+4=x\]
Subtract 4 to move everything except the square root to teh other side. Then suare both sides. Caution: You WILL lose something. With the Square Root, x + 2 >= 0. You no longer can see this after squaring.
yeah i know how to do that. but when i square does x-4 turn to (x-4)(x+4) and then we use the FOIL method?
Why would a SQUARE turn into something else? \(x+2 = (x-4)^{2} = (x-4)(x-4)\)
ok i went towards x-4 route and in the end i get\[\sqrt{8}+4=-6\] and \[\sqrt{5}+4=3\]
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That makes no sense. Please include intermediate steps so we can see where you wandered off.
uh whatever i just checked my work and i fixed something and now im figuring out the right answer
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