Question

Write the equation of the line with a slope of -1/3 and passing through the point (6, -4).

Answer 1

y-y1=m(x-x1)

Answer 2

wait im confused to what that is?

Answer 3

m is the slope and x1,y1 the point u have

Answer 4

im not exactly understanding..."/

Answer 5

what is the slope?

Answer 6

-1/3

Answer 7

ok plug that into

y-y1=m(x-x1)

now what is the x and y values?

Answer 8

0,3?

Answer 9

In that formula..
m = slope

Answer 10

@itsjustme_lol can you plug in everything into that formula now?

Answer 11

so m=-1/3

Answer 12

Right.... and you know what x1 and y1 are since they gave you the coordinates. So plug it in....

y-y1=m(x-x1)

Answer 13

y-4=m(x-6)?

Answer 14

y-(-4)=-1/3(x-6)

y+4=-1/3(x-6)

@itsjustme_lol do you understand that?

Answer 15

why did we put +4 in the second one?

Answer 16

y-(-4) = y+4

Answer 17

two negatives makes a positive

Answer 18

It is a negative being multiplied by a negative. That is something you should be familiar with.

Answer 19

y+4=-1/3(x-6)

Can you simplify the right side of this equation?

Answer 20

give me a second

Answer 21

wait im still confused. im sorry!!!

Answer 22

It is fine.

Answer 23

What are you confused about?

Answer 24

i dont know how to solve that equation

Answer 25

y+4=-1/3(x-6)

*We must first distribute that -1/3 on the right side of the equation.

y+4=-1/3x+2

Now we need to make this equation into the slope-intercept form... so y=mx+b... so lets subtract the 4 from both sides.

y+4=-1/3x+2
-4 -4
---------------------
y=-1/3x-2

Answer 26

@itsjustme_lol do you understand?

Answer 27

that makes sense now