Question

use the method of substitution to solve the system of linear equations
6a=3-b
6a=4-b

multiple answers are given
(a) there is one solution and the solution is (ordered pair)
(b) there are intfantly many solutions
(c) no solution

Answer 1

it should be (a)

Answer 2

artix if the answer is a what would the ordered pair be

Answer 3

from eqn 1, express b in terms of a, u get b=-2a, substitute that into eqn 2 and u get a=1 and b =-2

Answer 4

Solve the first eq for be by first subtracting 3 from both sides:
6a - 3 = -b
Now multiply both sides by -1:
-6a + 3 = b
Now rewrite as b = -6a + 3
Since you now know that b = -6a + 3, insert that value of b into b in the second equation:
6a = 4 - (-6a +3) and solve for a
6a = 4 + 6a -3
Collect like terms on right side:
6a = 1 + 6a
Now subtract 6a from both sides:
6a - 6a = 1 + 6a - 6a and you get
0 = 1
Since this is a flase statement, that means there is no solution.