Question

write an equation for the line that is perpendicular to the given line and that passes through the given point
-10x+8y=3;(15,12)

Answer 1

Start by finding the slope of the line.

Answer 2

How do I do that

Answer 3

-10x+8y=3....slope is 5/4.
You are looking for a line that is perpendicular to that slope, so that means the new slope would be -4/5

Answer 4

now use that new slope and the given point (15,12) and plug it into the point slope formula.

Answer 5

so, (y-12)=-4/5(x-15)

Answer 6

so the new equation would be:

Answer 7

y=-4/5x+24

Answer 8

How did u get the slope

Answer 9

Hello mr how do you find the slope of the line :)

Answer 10

solve the equation for y. -10x+8y=3

-10x+8y=3
add 10x to both sides
8y=10x+3

Answer 11

now divide both sides by 8

Answer 12

y=(10x+3)/8
or 10/8x+3/8
this reduces to y=5/4x+3/8

Answer 13

This new equation: y=5/4x+3/8 is in y intercept form, where y=mx+b, m represents the slope.....5/4

Answer 14

Yay I got that. Sorry I would have u a medal but I can't now when I am gonna be on the desk top then I'll be your fan
~thanks so much :)

Answer 15

Is that it ?

Answer 16

Hello???

Answer 17

Okay so now I'm not ont desktop but I just realized I can give u amedal with the phone